Power of lens | Units | Combination in series and parallel - Param Himalaya
Power of a lens
Power of a lens is a measure of the convergence or divergence.
The power $P$ of a lens is defined as the tangent of the angle by which it converges or diverges a beam of light parallel to the principal axis falling at unit distance from the optical centre.
$\tan \delta = \frac{h}{f}$
if h = 1 then
$\tan \delta = \frac{1}{f} \text{ or } \delta = \frac{1}{f}$
$\text{ for small } \delta.$
That is,
$P = \frac{1}{f_{(\text{in m})}} \quad \dots (i)$
or,
$P = \frac{100}{f_{(\text{in cm})}}$
As per lens maker's formula, the focal length of a lens is given by
$\frac{1}{f} = (n-1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$
$\therefore$ Power of lens,
$P = \frac{1}{f} = (n-1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right) \quad \dots (ii)$
Thus, power of a lens is more if its focal length is small and power of a lens is less if its focal length is large.
SI unit of power :
The SI unit of power is dioptre and denoted by D.
$P = 1$ dioptre if $f = 1$ metre
Thus, the power of lens is 1 dioptre if its focal length is 1 metre.
$1 \text{ D} = 1 \text{ m}^{-1}$
A lens of short focal length has more power whereas a lens of long focal length has less power.
The power of a convex lens is positive
The power of a concave lens is negative.
In order to calculate the power of a lens , we need its focal length in metres.
Power of a combination of lenses :
1.If two lenses are placed in contact , the combination has a power equal to the algebraic sum of the powers of two lenses.
P = P1+ P2 , 1/f = 1/f1 + 1/f2