Electric Field Intensity due to a System of Charges (Principle of Superposition)

Electric Field Intensity due to a System of Charges (Principle of Superposition)

Electric Field Intensity due to a System of Charges (Principle of Superposition)

Question: Find an expression for electric field intensity at a point due to a system of point charges.

Principle of Superposition of Electric Fields: According to the principle of superposition, net electric field strength at a point due to a group of point charges is equal to the vector sum of all the electric field strengths produced due to individual point charges at that point.

Principle of Superposition of Electric Fields:

Suppose we have $n$ point charges $q_1, q_2, \ldots, q_n$ such that their position vectors are $\vec{r}_1, \vec{r}_2, \ldots, \vec{r}_n$ respectively. Let $q_0$ be the positive test charge at point $P$ where the total electric field $\vec{E}$ due to $n$ charges is to be determined. Let the position vector of the point $P$ be $\vec{r}$ .

Electric fields due to point charges $q_1, q_2, \ldots, q_n$ respectively at point $P$ are given by,

$\vec{E}_1= \frac{1}{4\pi\epsilon_0} \frac{q_1(\vec{r} - \vec{r}_1)}{|\vec{r} - \vec{r}_1|^3} $

$\vec{E}_2= \frac{1}{4\pi\epsilon_0} \frac{q_2(\vec{r} - \vec{r}_2)}{|\vec{r} - \vec{r}_2|^3}$

$\vec{E}_n= \frac{1}{4\pi\epsilon_0} \frac{q_n(\vec{r} - \vec{r}_n)}{|\vec{r} - \vec{r}_n|^3} $

and

Therefore, resultant electric field at point P is given by

$\vec{E} = \vec{E}_1 + \vec{E}_2 + \dots + \vec{E}_n$

$\vec{E}= \frac{1}{4\pi\epsilon_0} \frac{q_1(\vec{r} - \vec{r}_1)}{|\vec{r} - \vec{r}_1|^3}+ \frac{1}{4\pi\epsilon_0} \frac{q_2(\vec{r} - \vec{r}_2)}{|\vec{r} - \vec{r}_2|^3}+$

 $\dots + \frac{1}{4\pi\epsilon_0} \frac{q_n(\vec{r} - \vec{r}_n)}{|\vec{r} - \vec{r}_n|^3}$

$\vec{E}= \frac{1}{4\pi\epsilon_0} \sum_{i=1}^n \frac{q_i(\vec{r} - \vec{r}_i)}{|\vec{r} - \vec{r}_i|^3} \qquad \dots (i)$

or

which is the required expression for the electric field intensity due to a system of $n$ point charge.

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