Derivation: Combination of Thin Lenses in Contact Equivalent Focal length, Power and Magnification

Derivation: Combination of Thin Lenses in Contact Equivalent Focal length, Power and Magnification

Combination of Thin Lenses in Contact Equivalent Focal length, Power and Magnification 

(i) Equivalent focal length of the combination of Lenses : 

Combination of Thin Lenses in Contact Equivalent Focal length, Power and Magnification

Consider two thin lenses of focal lengths $f_1$ and $f_2$ respectively, placed in contact with each other . Let $O$ be the point object placed on the principal axis of the lenses in contact. If the first lens forms an image $I_1$ of the object $O$ at a distance $v_1$ from it.

$\frac{1}{v_1} - \frac{1}{u} = \frac{1}{f_1} \quad \text{(Lens formula)} \quad \dots (i)$

Since the second lens is in contact with the first, so $I_1$ acts as a virtual object for the second lens which forms the image $I$ at a distance $v$ from it.

$\frac{1}{v} - \frac{1}{v_1} = \frac{1}{f_2} \quad \dots (ii)$

Adding eqs. (i) and (ii), we get

$\frac{1}{v_1} - \frac{1}{u} +\frac{1}{v} - \frac{1}{v_1}$

$\frac{1}{v} - \frac{1}{u} = \frac{1}{f_1} + \frac{1}{f_2}$

or

$\frac{1}{F} = $\frac{1}{v} - \frac{1}{u} \quad \dots (iii)$

Where $\frac{1}{F} = \frac{1}{f_1} + \frac{1}{f_2} \quad \dots (iv)$

here $F$ is the effective focal length or equivalent focal length of the combination of two lenses in contact.

Thus, the two thin lenses in contact behave as a single lens known as equivalent lens with focal length $F$ called equivalent focal length.

If more than two lenses are in contact, then the equivalent focal length of the combination is given by

$\frac{1}{F} = \frac{1}{f_1} + \frac{1}{f_2} + \frac{1}{f_3} + \dots \quad \dots (v)$

(ii) Power of the Equivalent Lens : 

Power of a lens is given by, 

$P = \frac{1}{f} \quad \dots (i)

where $f$ is the focal length of the lens.

If two lenses are in contact, then the focal length of the equivalent lens formed by these two lenses is given by

$\frac{1}{F} = \frac{1}{f_1} + \frac{1}{f_2} \quad \dots (ii)$

Using eqn. (i), we get

$P = P_1 + P_2 \quad \dots (iii)

If more than two lenses are in contact, then the power of the equivalent lens is given by

$P = P_1 + P_2 + P_3 + \dots \quad \dots (iv)$

Thus, power of an equivalent lens is the algebraic sum of the powers of individual lenses in contact.

(iii) Magnification of the Equivalent Lens : 

Consider two lenses $L_1$ and $L_2$ in contact having linear magnifications $m_1$ and $m_2$ respectively. Then the net linear magnification of an equivalent lens formed by two lenses in contact is given by

m = m_1 \times m_2 \quad \dots (i)

If equivalent lens is formed by more than two lenses, then the net linear magnification is given by

$m = m_1 \times m_2 \times m_3 \times \dots \quad \dots (ii)$

Thus, the combination of lenses magnifies the final image.

(iv) Uses of Equivalent Lens : 

Equivalent lens (i.e., combination of lenses) is used in optical instruments like telescope, microscope, camera and binoculars to get sharp images of the objects.

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